Mathématiques

Question

bonjour, aidez moi svp:

devellopper et réduire:

A=(a-12+b)-(-12-a+b)+(b+1)

B=9-(x-3+y)+(x-7)

C=3(2+a)-(6-3a)+4(1-2a)

D=(2a+3)(1-3a)+3(3+2a)

E=5-(4-(3a-5)+(a+5))

2 Réponse

  • A=(a-12+b)-(-12-a+b)+(b+1)
    A= a -12 +b +12 +a -b +b +1
    A= 2a +b +1

    B=9-(x-3+y)+(x-7)
    B= 9 - x +3 -y +x -7
    B= -y +5

    C=3(2+a)-(6-3a)+4(1-2a)
    C= 6 +3a -6 +3a +4 -8a
    C=-2a +4

    D=(2a+3)(1-3a)+3(3+2a)
    D= 2a -6a² +3 -9a +9 +6a
    D= -6a² - a +12

    E=5-(4-(3a-5)+(a+5))
    E= 5 - ( 4 -3a +5 +a +5)
    E= 5- 4 +3a -5 -a -5
    E= 2a -9
  • A=(a-12+b)-(-12-a+b)+(b+1)
    A = a-12+b+12+a-b+b+1
    A = 2a+b+1

    B=9-(x-3+y)+(x-7)
    B = 9-x+3-y+x-7
    B = 5-y

    C=3(2+a)-(6-3a)+4(1-2a)
    C = 6+3a-6+a+4-8a
    C = 16 -4a

    D=(2a+3)(1-3a)+3(3+2a)
    D = 2a-6a²+3-9a+9+6a
    D = 12-a-6a²

    E=5-(4-(3a-5)+(a+5))
    E = 5-4+3a+5-a-5
    E = 2a+1

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